course Phy 201
I apologize that my work is out of order. I had done this work previously and saved it to my computer and I just got my internet fix yesterday.
Assign. 4, Version 7A bee is making a beeline for its hive. Its velocity is measured at a distance of 83 meters from the observer, when clock time is t = 3 sec and its velocity is 4 m/s, and again at clock time t = 8 sec. It it accelerates uniformly at .9 m/s/s during the time interval, then what is its velocity at t = 8 sec, and its average velocity during this time interval? How far is the bee from the observer at t = 8 sec?
Your work has been received. Please scroll through the document to see any inserted notes (inserted at the appropriate place in the document, in boldface) and a note at the end. The note at the end of the file will confirm that the file has been reviewed; be sure to read that note. If there is no note at the end, notify the instructor through the Submit Work form, and include the date of the posting to your access page.
First we have to find the final distance. We do this by solving for x in the following equation provided in Chapter 2 Pg. 27 of the textbook.
X = 83 m + 4m/s(8s) + ½(.9 m/s^2)(8s)^2
= 83 m +32 m/s^2 +28.8 m/s^2
= 143.8 m
By solving for X we can now solve for the velocity at t=8 from another equation provided in chapter 2.
V^2 = (4m/s)^2 + 2(.9 m/s^2)(143.8 m – 83m)
= 16 m^2/s^2 + (1.8 m/s^2)(60.8 m)
= 16 m^2/s^2 + 109.44 m^2/s^2
Next take the square root of both sides and we get,
V = 11.2 m/s
- Therefore, the velocity at clock time t=8 seconds is 11.2 m/s.
- The average velocity is
vAve = `ds/`dt
= 11.2 m/s + 4 m/s / 2
= 22.4 m/s
- At clock time t=8 seconds the bee is 60.8 m from the observer; 143.8m-83m = 60.8m
"
end of document
Your work has not been reviewed.
Please notify your instructor of the error, using the Submit Work form, and be sure to include the date 06-28-2008.
This looks good.
&#Let me know if you have questions. &#