Assign 18

course Mth 158

Just wanted to let you know that this assignment 18 and q-a program 18 did not match up. The assignment 18 in the text was on chapter 2 section 2.3 circles, and this q-a program was on slopes in chapter 2 section 2.4 lines.

b̠~Ubpassignment #018

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018. `query 18

College Algebra

03-07-2007

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assignment #018

018. `query 18

College Algebra

03-07-2007

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13:02:08

2.4.30 (was 2.3.24). Slope 4/3, point (-3,2)

Give the three points you found on this line and explain how you obtained them.

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RESPONSE -->

Slope=4/3 x increases by 3 and y increases by 4

original point (-3,2) (-3,2)slpoe=4/3=-4/3

x= -3+3=0 x=0+3=3 x=-3-3=-6

y=2+4=6 y=6+4=10 y=2-4=-2

(0,6) (3,10) (-6,-2)

confidence assessment: 2

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13:02:31

STUDENT SOLUTION:

(-3,2) slope 4/3. Move 3 units in the x direction, 4 in the y direction to get

((-3+3), (2+4)), which simplifies to

(0,6)

(-3,2) slope 4/3 = -4/-3 so move -3 units in the x direction and -4 in the y direction to get

((-3-3), (2-4)) which simplifies to

(-6,-2)

From (0,6) with slope 4/3 we move 4 units in the y direction and 3 in the x direction to get

((0+3), (6+4)), which simplifies to

(3,10). The three points I obtained are

(-6,-2), (0,6), (3,10).

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RESPONSE -->

okay

self critique assessment: 2

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13:11:40

query 2.4.36 (was 2.3.30). Line thru (-1,1) and (2,2) **** Give the equation of the line and explain how you found the equation.

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RESPONSE -->

slope,m=(y2-y1)/(x2-x1)= Rise/Run x1 can not = x2

m=(2-1)/2-(-1))

m=1/3

y=y1=m(x-x1)

m=1/3

(x1,y1)=(-1,1)

y-1=1/3(x+)1

y=1/3+4/3

confidence assessment: 2

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13:11:55

STUDENT SOLUTION: The slope is m = (y2 - y1) / (x2 - x1) = (2-1)/(2- -1) = 1/3.

Point-slope form gives us

y - y1 = m (x - x1); using m = 1/3 and (x1, y1) = (-1, 1) we get

y-1=1/3(x+1), which can be solved for y to obtain

y = 1/3 x + 4/3.

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RESPONSE -->

yeah!

self critique assessment: 2

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13:16:51

2.4.46 (was 2.3.40). x-int -4, y-int 4 **** What is the equation of the line through the given points and how did you find the equation?

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RESPONSE -->

x-intercept; -4

y-intercept; 4

(0,4),(-4,0)

slope=m=rise/run

m=(-4-0)/(0+4)

(y2 - y1) (x2 - x1) = (4 - 0) / (0 - (-4) ) = 4 / 4 = 1.

m=1

y=mx+b

y=1x+4

y=x+4

confidence assessment: 2

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13:18:18

STUDENT SOLUTION: The two points are (0, 4) and (4, 0). The slope is therefore m=rise / run = (4-0)/(0+4) = 1.

The slope-intercept form is therefore y = m x + b = 1 x + 4, simplifying to

y=x+4.

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RESPONSE -->

ok shouldn't it be -1 because the x-intercept of -4 not 4???anyways...from was right!

self critique assessment: 2

See my note. Also take a few seconds and sketch the two intercepts and the line between them. That should clarify everything for you.

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13:21:17

2.4.56 (was 2.4.48). y = 2x + 1/2. **** What are the slope and the y-intercept of your line and how did you find them?

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RESPONSE -->

y=mx+b

y=2x+1/2

slope is m=2

y-intercept, let x=0

y=2(0)+1/2

y=1/2

y-intercept (0,1/2)

confidence assessment: 2

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13:21:25

** the y intercept occurs where x = 0, which happens when y = 2 (0) + 1/2 or y = 1/2. So the y-intercept is (0, 1/2).

The slope is m = 2.**

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RESPONSE -->

self critique assessment: 2

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"

Very good. See my notes and let me know if you have questions.