course Mth 158 Just wanted to let you know that this assignment 18 and q-a program 18 did not match up. The assignment 18 in the text was on chapter 2 section 2.3 circles, and this q-a program was on slopes in chapter 2 section 2.4 lines. b̠~Ubpassignment #018
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13:02:08 2.4.30 (was 2.3.24). Slope 4/3, point (-3,2) Give the three points you found on this line and explain how you obtained them.
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RESPONSE --> Slope=4/3 x increases by 3 and y increases by 4 original point (-3,2) (-3,2)slpoe=4/3=-4/3 x= -3+3=0 x=0+3=3 x=-3-3=-6 y=2+4=6 y=6+4=10 y=2-4=-2 (0,6) (3,10) (-6,-2) confidence assessment: 2
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13:02:31 STUDENT SOLUTION: (-3,2) slope 4/3. Move 3 units in the x direction, 4 in the y direction to get ((-3+3), (2+4)), which simplifies to (0,6) (-3,2) slope 4/3 = -4/-3 so move -3 units in the x direction and -4 in the y direction to get ((-3-3), (2-4)) which simplifies to (-6,-2) From (0,6) with slope 4/3 we move 4 units in the y direction and 3 in the x direction to get ((0+3), (6+4)), which simplifies to (3,10). The three points I obtained are (-6,-2), (0,6), (3,10).
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RESPONSE --> okay self critique assessment: 2
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13:11:40 query 2.4.36 (was 2.3.30). Line thru (-1,1) and (2,2) **** Give the equation of the line and explain how you found the equation.
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RESPONSE --> slope,m=(y2-y1)/(x2-x1)= Rise/Run x1 can not = x2 m=(2-1)/2-(-1)) m=1/3 y=y1=m(x-x1) m=1/3 (x1,y1)=(-1,1) y-1=1/3(x+)1 y=1/3+4/3 confidence assessment: 2
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13:11:55 STUDENT SOLUTION: The slope is m = (y2 - y1) / (x2 - x1) = (2-1)/(2- -1) = 1/3. Point-slope form gives us y - y1 = m (x - x1); using m = 1/3 and (x1, y1) = (-1, 1) we get y-1=1/3(x+1), which can be solved for y to obtain y = 1/3 x + 4/3.
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RESPONSE --> yeah! self critique assessment: 2
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13:16:51 2.4.46 (was 2.3.40). x-int -4, y-int 4 **** What is the equation of the line through the given points and how did you find the equation?
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RESPONSE --> x-intercept; -4 y-intercept; 4 (0,4),(-4,0) slope=m=rise/run m=(-4-0)/(0+4)
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13:18:18 STUDENT SOLUTION: The two points are (0, 4) and (4, 0). The slope is therefore m=rise / run = (4-0)/(0+4) = 1. The slope-intercept form is therefore y = m x + b = 1 x + 4, simplifying to y=x+4.
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RESPONSE --> ok shouldn't it be -1 because the x-intercept of -4 not 4???anyways...from was right! self critique assessment: 2
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13:21:17 2.4.56 (was 2.4.48). y = 2x + 1/2. **** What are the slope and the y-intercept of your line and how did you find them?
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RESPONSE --> y=mx+b y=2x+1/2 slope is m=2 y-intercept, let x=0 y=2(0)+1/2 y=1/2 y-intercept (0,1/2) confidence assessment: 2
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13:21:25 ** the y intercept occurs where x = 0, which happens when y = 2 (0) + 1/2 or y = 1/2. So the y-intercept is (0, 1/2). The slope is m = 2.**
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RESPONSE --> self critique assessment: 2
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