Phy 231
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A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.
• What is your best guess about the ball's average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
I am going to say 7 cm/sec because it is the average of the start and final velocities. (10+4)/2 = 7.
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• Without further information, why is this just a guess?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
There needs to be more information. The distance plays a large factor and time also affects the values.
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• If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The second velocity is 10 and the first velocity is 4. The difference in the two is 10-4 which is 6 cm/sec. To find how far it traveled in that time, I would just need to multiply the difference result by 3 seconds. Therefore, I would get 6*3 = 18. 18 cm is the final result.
change in velocity is not related to how far an object travels (you can go a long way at 70 mph without any change in speed); average velocity is related to how far
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• At what average rate did its velocity change with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Once again the difference in the two velocities plays a part in finding the result. 6 cm/sec is the difference. To find the average rate that the velocity changed I would take the difference and divide it by the time given. 6/3 = 2. The results comes out to be 2 cm/sec per second.
Good. This is a correct use of the change in velocity.
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18 mins
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Solution
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