Phy 231
Your 'cq_1_03.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball starts with velocity 0 and accelerates uniformly down a ramp of length 30 cm, covering the distance in 5 seconds.
• What is its average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The average velocity is found by using the equation v = d/t. The distance is 30 cm and the time is 5 seconds. 30/5 = 6 cm/sec. The average velocity is 6 cm/sec.
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• If the acceleration of the ball is uniform then its average velocity is equal to the average of its initial and final velocities.
You know its average velocity, and you know the initial velocity is zero.
What therefore must be the final velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The final velocity must be the same as the average velocity will just be double the average velocity because the initial velocity is 0 it will not necessarily have an individual affect on the final velocity. Therefore, (6 cm/sec + 0 cm/sec) * 2 = 12 cm/sec. The final velocity is 12 cm/sec.
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• By how much did its velocity therefore change?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The velocity changed by 12 cm/s because it started off being 0 cm/s and ended as 12 cm/s.
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• At what average rate did its velocity change with respect to clock time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The velocity changed with respect to clock time the amount of 2.4 cm/s. This was found by taking the average velocity, 12 cm/sec and dividing it by the total time which was 5 seconds.
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• What would a graph of its velocity vs. clock time look like? Give the best description you can.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The graph of its velocity vs. clock time would be a linear graph. It would start at (0,0) and end at (5,12). The slope of the graph throughout the entire line would be 2.4 because this was the average rate of change which happens to be the same thing as the slope.
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15 mins
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&#Very good responses. Let me know if you have questions. &#