Phy 231
Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
36 cm/s will be the velocity. I found this by plugging in the values accordingly into the kinematic equation vf = 12 + 8t.
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• Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
If the acceleration is constant, the average velocity during the time interval will amount to 24 cm/s. I found this by taking the initial velocity which was 12 cm/s and finding the average of it with another velocity that was found, 36 cm/s. Therefore 48 cm/s / 2 = 24 cm/s.
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• How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
During this time interval, it will travel 72 cm. I found this by taking the average velocity, 24 cm/s and multiplying it by the time which was 3 seconds. As a result, 24*3 is 72 centimeters.
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20 mins
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This looks very good. Let me know if you have any questions.