Phy 231
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
The velocity is 2m /0.64 sec = 3.125 m/s. To find the acceleration, I will take the change in velocity which I then can divide by the time interval, which is 6.25 m/s / 0.64 sec I get 9.77 m/s/s as the acceleration.
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• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
If the initial velocity is at 0 once again, then I would just do the same and get 9.07 m/s^2 as the acceleration.
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• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
The first problem is consistent with the accepted value of the acceleration of gravity in the sense that the difference is only 0.03 m/s^2 which could be from small errors. The other problem though, has a greater difference, 0.73 m/s^2, which makes it not too likely that it is consistent with the accepted value of the acceleration of gravity.
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30 mins
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