Phy 231
Your 'cq_1_19.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Sketch a vector representing a 10 Newton force which acts vertically downward.
• Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.
answer/question/discussion: ->->->->->->->->->->->-> :
Since the vector is 250 degrees, it will be in the 3rd quadrant. The x projection heads down and the y projection heads to the left. The vector itself looks like it is 20 degrees to the left of the y axis. I found this by taking 270-250 = 20 degrees.
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• What are the x and y components of the equilibrant of the force?
answer/question/discussion: ->->->->->->->->->->->-> :
x is 10 N * cos(250) = -3.4 N
y is 10 N * sin(250) = -9.4 N
3.4 N and 9.4 N respectively
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10 mins
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&#This looks very good. Let me know if you have any questions. &#