course phy 201 didn't realize that i must have skipped over this one, sorry. QwxzFzassignment #001
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22:22:36 Explain in your own words how the standard deviation of a set of numbers is calculuated.
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RESPONSE --> You add all of the numbers together and divide by the quantity of numbers. Also known as the average. confidence assessment: 3
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22:25:23 Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.
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RESPONSE --> You take the best fit straight line, which may differ from person to person, and find two points on that line. With the two points you can find the slope, (deviation of y values over the deviation of x values). with this information you can use the formula y=mx+b to find the vertical intercept. since different numbers will be used by each person for the two points, the slope and intercept will vary. confidence assessment: 3
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22:27:06 Briefly state what you think velocity is and how you think it is an example of a rate.
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RESPONSE --> velocity is the rate of change in distance to the change in time. in other words, it is how much distance is traveled in a period of time. confidence assessment: 3
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22:27:23 ** A rate is a change in something divided by a change in something else. This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **
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RESPONSE --> self critique assessment: 3
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22:30:07 Given average speed and time interval how do you find distance moved?
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RESPONSE --> with the average velocity given, and the time interval, you can reverse the previous equation [(d2-d1)/(t2-t1)=v] --> [(delta D) = V*(delta T)]. simply stated, the speed multiplied by how long it was moving at that speed. confidence assessment: 3
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22:30:15 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
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RESPONSE --> ok self critique assessment: 3
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22:31:15 Given average speed and distance moved how do you find the corresponding time interval?
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RESPONSE --> [V = (delta D)/(delta T)] --> [(delta T) = (delta D)/V] confidence assessment: 3
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22:31:29 ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
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RESPONSE --> ok self critique assessment: 3
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22:31:55 Given time interval and distance moved how do you get average speed?
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RESPONSE --> average speed = distance moved / time interval confidence assessment: 3
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22:32:02 ** Average speed = distance / change in clock time. This is the definition of average speed. For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **
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RESPONSE --> ok self critique assessment: 3
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xpDvЃI׃ʱ assignment #001 001. Physics I 02-05-2009
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22:34:48 Explain in your own words how the standard deviation of a set of numbers is calculuated.
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RESPONSE --> confidence assessment:
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