cq_1_051

phy 201

Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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10 min

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The problem:

A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.

• What will be its velocity after the 3 seconds has elapsed?

answer/question/discussion: 8 cm/s^2 * (3 sec) = 24 cm/s velocity change in three seconds. 24 cm/s + 12 cm/s = 36 cm/s = velocity after 3 seconds has elapsed.

• Assuming that acceleration is constant, what will be its average velocity during this interval?

answer/question/discussion: vAve = (12 cm/s + 36 cm/s) / 2 = 24 cm/s.

• How far will it travel during this interval?

answer/question/discussion: it will travel at 24 cm/s for 3 seconds, finishing up (24*3) 72 cm farther.

&#Your work looks very good. Let me know if you have any questions. &#