phy 201
Your 'cq_1_7.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion:
‘dt = .64 s
v0 = 0 m/s
vf = 2/.64 = 3.125 m/s
This is the average velocity, not the final velocity.
a = (vf-v0) / ‘dt = 3.125 / .64 = 4.88 m/s^2
• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion:
no, the acceleration is too high for the final 3 meters falling in .41 seconds. This would mean that the final velocity is 11.51 m/s and the acceleration is 20.45 m/s^2.
• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion:
no, the answer I got for the total fall for acceleration is 4.53 m/s^2 which is not consistent with the law of gravity.
** **
15 min.
** **
not sure about these answers but i used logic and what i thought was common sense to figure it out.
You need to recalculate your acceleration for the first situation, and you need to actually calculate the acceleration of the object in the second situation.
&#Please see my notes and submit a copy of this document with revisions and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end). &#