phy 201
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Answer the following based on Newton's Second Law:
• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion:
F = m*a = 12 * 3 = 36 N
• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion:
F = m*a
a = F/m = 20 / 4 = 5 m/s^2
• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion:
F = 20 N
m = 10 kg
a = 1.5 m/s^2
a = F/m = 2 m/s^2; this is the actual acceleration with the data given. Since the measured acceleration is .5 less, then there must be a force acting in the opposite direction slowing down the acceleration.
• What is the total of all those forces and in what direction does this total act?
answer/question/discussion:
Fnet = F – Ffric
F is acting in the direction the force was exerted. The friction force is acting in the opposite direction. The net force is the sum of these two which results in 20 N forward (to the right) and 5 N backward (to the left), resulting in 15 N forward, or to the right.
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20 min.
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&#Very good work. Let me know if you have questions. &#