phy 201
Your 'cq_1_25.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A steel ball of mass 110 grams moves with a speed of 30 cm / second around a circle of radius 20 cm.
• What are the magnitude and direction of the centripetal acceleration of the ball?
answer/question/discussion:
A = v^2 / r
A = 900/20 = 45 m/s/s
F = 45(110) = 4950 N
Direction is away from center…
• What is the magnitude and direction of the centripetal force required to keep it moving around this circle?
answer/question/discussion:
I believe the magnitude would be the same but it would be a reverse force from the string holding the ball at the same distance from the center of the circle.
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15 min
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You could twirl a ball of that mass at that speed on a length of nylon twine. Neither you nor the twine is capable of exerting a force of 4950 N (over 1000 lbs). Your error is most likely due to incorrect units.
No need to submit a revision as long as you understand, but be sure to compare with the link below.
&#At least part of your solution does not agree with the solution and comments given at the link below. You should view the solution at that link and self-critique as indicated there.
Solution
This link also expands on these topics and alerts you to many of the common errors made by students in the first part of this course. &#