PHY 201
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A steel ball of mass 110 grams moves with a speed of 30 cm / second around a circle of radius 20 cm.
• What are the magnitude and direction of the centripetal acceleration of the ball?
answer/question/discussion:
a=v^2/r = (.30m/s)^2/.20m = .45m/s^2
The direction is toward the center of the circle.
• What is the magnitude and direction of the centripetal force required to keep it moving around this circle?
answer/question/discussion:
a=F/m so F=a*m = .45m/s^2*.110kg = .0495N
The direction is toward the center of the circle.
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20 min
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