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A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
What is the clock time at the midpoint of this interval?
answer/question/discussion:
9 sec because that is the midpoint between 5 and 13
What is the velocity at the midpoint of this interval?
answer/question/discussion:
24cm/s because that is the intersection of the 9 s midpoint and the velocity
How far do you think the object travels during this interval?
answer/question/discussion:
52cm
This is not correct and it's unclear how you got this result. Remember to show how you obtain your results so I can address the specifics of any errors you might make, and any misunderstandings your documentation might suggest.
By how much does the clock time change during this interval?
answer/question/discussion:
8 sec
By how much does velocity change during this interval?
answer/question/discussion:
24cm/s
What is the rise of the graph between these points?
answer/question/discussion:
24
What is the run of the graph between these points?
answer/question/discussion:
8
What is the slope of the graph between these points?
answer/question/discussion:
3
The coordinates of this graph have units, so the rise and the run have units, which should always be specified.
In this case, as I'm sure you understand, the rise has units of cm/s, the run has units of s, and the slope therefore has units of (cm/s) / s = cm/s^2.
What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion:
The motion is increasing
What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion:
3 cm/s/s
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17 minutes
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You have one result that appears to be incorrect.
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