PHY201
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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion:
Assuming uniform acceleration then aavg = ‘dv / ‘dt
8cm/s/s = (vf – v0) / 3s
8cm/s/s = (vf-12cm/s)/3s
8cm/s/s * 3s = vf – 12cm/s
24cm/s + 12 cm/s = vf
36cm/s = vf
• Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion:
vavg = (vf + v0) / 2
vavg = (36cm/s + 12cm/s) /2 = 24 cm/s
• How far will it travel during this interval?
answer/question/discussion:
vavg = ‘ds/’dt
24cm/s = ‘ds/3s
24cm/s * 3s = ‘ds
72cm = ‘ds
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7 minutes
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