PHY 201
Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Seed Question 10.1
A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
• How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
answer/question/discussion:
From one extreme point to the other = ½*2s = 1s
From one extreme point to equilibrium = ½ * 1s = 0.5s or ¼ * 2s = 0.5s
From one extreme point to the other and back to equilibrium = ¾ * 2s = 1.5s
• What reasonable assumption did you make to arrive at your answers?
answer/question/discussion:
The swinging pendulum has three points equal distance apart; Point A being the right extreme point, Point B being the equilibrium point, and Point C being the left extreme point. The swinging pendulum makes 4 equal movements in one cycle; from point A to point B, from point B to point C, from point C to point B, and from point B to point A. Therefore there are 4 movements in the 2 sec. To move from one extreme to the other extreme is 2/4 or ½ movements. To move from one extreme point to equilibrium is ¼ movement. To move from one extreme point to the other and back to equilibrium is ¾ movements. Multiply the movements by the 2s to obtain the time.
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30 minutes
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&#Very good responses. Let me know if you have questions. &#