PHY 201
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion:
The 6kg mass will accelerate downward and the 5 kg mass will accelerate upward.
Force on 5kg mass side = 5kg * 9.8m/s^2 = 49N
Force on 6kg mass side = 6kg * 9.8m/s^2 = 58.8N
Net force on system = 58.8N – 49N = 9.8N
Acceleration of system = 9.8N / 11kg = 0.89m/s^2 in the direction of the 6kg mass.
• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion:
v0 = 1.8m/s
v=v0-AT
v=1.8m/s – 0.89m/s^2*1s = 0.91m/s
The motion will be in the direction of the 5kg mass.
• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion:
During the first second, the velocity and acceleration of the system are in opposite directions and the system is speeding up.
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1.5 hours
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&#Very good responses. Let me know if you have questions. &#
PHY 201
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion:
The 6kg mass will accelerate downward and the 5 kg mass will accelerate upward.
Force on 5kg mass side = 5kg * 9.8m/s^2 = 49N
Force on 6kg mass side = 6kg * 9.8m/s^2 = 58.8N
Net force on system = 58.8N – 49N = 9.8N
Acceleration of system = 9.8N / 11kg = 0.89m/s^2 in the direction of the 6kg mass.
• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion:
v0 = 1.8m/s
v=v0-AT
v=1.8m/s – 0.89m/s^2*1s = 0.91m/s
The motion will be in the direction of the 5kg mass.
• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion:
During the first second, the velocity and acceleration of the system are in opposite directions and the system is speeding up.
** **
1.5 hours
** **
&#Very good responses. Let me know if you have questions. &#