phy 201
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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
->->->->->->->->->->->-> answer/question/discussion:
8cm/sec^2 = (vf-12cm/sec) / 3 sec
8 cm/sec^2 * 3 sec = vf – 12cm/sec
24 cm/sec = vf -12 cm/sec
Final velocity = 36 cm/sec
• Assuming that acceleration is constant, what will be its average velocity during this interval?
->->->->->->->->->->->-> answer/question/discussion:
vAve = (108 cm- 0 cm)/ 3 sec
vAve= 36 cm/sec
• How far will it travel during this interval?
->->->->->->->->->->->-> answer/question/discussion:
36 cm/sec = `ds / 3sec
`ds = 108 cm
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10 minutes
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&#This looks good. Let me know if you have any questions. &#