Asst 8 qa

#$&*

course Mth 163

10/2 12

008.

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Question: `q001. Note that this assignment has 5 questions

For the function y = 1.1 x + .8, what are the coordinates of the x = 2 and x = 9 points? What is the rise between these points and what is the run between these points? What therefore is the slope between these points?

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Your solution:

y = 1.1(2) + .8 = 3

y = 1.1(9) + .8 = 10.7

(2, 3) and (9, 10.7)

Rise = 7.7

Run = 7

Slope = 1.1

confidence rating #$&*: 3

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Given Solution:

Evaluating y = 1.1 x +.8 for x = 2 and x = 9 we obtain y = 3 and y = 10.7. The graph points are therefore (2,3) and (9,10.7).

The rise between these points is 10.7 - 3 = 7.7 and the run is 9-2 = 7. Thus the slope is 7.7 / 7 = 1.1.

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Self-critique (if necessary):

ok

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Self-critique rating: ok

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Question: `q002. For the function y = 1.1 x + .8, what are the coordinates of the x = a point, in terms of the symbol a? What are the coordinates of the x = b point, in terms of the symbol b?

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Your solution:

The function for x = a would be y = 1.1a + .8

The function for x = b would be y = 1.1b + .8

The coordinates would be (a, 1.1a+.8) for x = a

The coordinates would be (b, 1.1b + .8) for x = b

confidence rating #$&*: 3

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Given Solution:

If x = a, then y = 1.1 x + .8 gives us y = 1.1 a + .8.

If x = b, then y = 1.1 x + .8 gives us y = 1.1 b + .8. Thus the coordinates of the x = a point are (a, 1.1 a + .8) and (b, 1.1 b + .8).

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Self-critique (if necessary):

ok

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Self-critique rating: ok

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Question: `q003. We see that the coordinates of the x = a point are (a, 1.1 a + .8) and (b, 1.1 b + .8). What therefore is the rise between these two points? What is the run between these two points?

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Your solution:

(1.1b + .8) - (1.1a + .8) = rise

b - a = run

confidence rating #$&*: 3

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Given Solution:

The rise between the points is the rise from y = 1.1 a + .8 to y = 1.1 b + .8, a rise of

rise = (1.1 b + .8) -(1.1 a + .8) = 1.1 b + .8 - 1.1 a - .8 = 1.1 b - 1.1 a.

The run is from x = a to x = b, a run of

run = b - a.

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Self-critique (if necessary):

ok

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Self-critique rating: ok

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Question: `q004. We see that the rise between the x = a and x = b points of the graph of y = 1.1x +.8 is 1.1 b + .8 - (1.1 a + .8), while the run is b - a. What therefore is the average slope of the graph between these points? Simplify your answer.

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Your solution:

slope = rise/run

slope = [1.1b + .8) - (1.1a + .8)] / b - a

= (1.1b - 1.1a) / b - a

= 1.1 - 1.1

= 0

Not sure I did this right.

confidence rating #$&*: 2

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Given Solution:

The slope is

slope = rise / run = (1.1 b - 1.1 a) / (b - a) = 1.1 (b - a) / (b - a) = 1.1.

The significance of this series of exercises is that the slope between any two points of the straight line y = 1.1 x + .8 must be 1.1, no matter whether the points are given by numbers (e.g., x = 2 and x = 9) or by symbols (x = a and x = b). Mostly

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Self-critique (if necessary):

I understand that I needed to do 1.1 (b-a) before cancelling out b and a to get the final answer 1.1. I have corrected this.

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Self-critique rating: ok

If you understand the assignment and were able to solve the previously given problems from your worksheets, you should be able to complete most of the following problems quickly and easily. If you experience difficulty with some of these problems, you will be given notes and we will work to resolve difficulties.

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Question: `q005. What are the rise, run and slope of the graph of the function

y = 3/2 x + 12

between x = 2 and x = 4?

In terms of the symbols a and b, what are the rise, run and slope of the graph of the same function between x = a and x = b?

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Your solution:

y = 3/2(2) + 12 = 15

y = 3/2 (4) + 12 = 18

(2, 15) (4, 18)

rise = 18 - 15 = 3

run = 4-2 = 2

slope = 3/2 = 1.5

For x = a and x = b

y = 3/2a + 12

y = 3/2b + 12

(a, 3/2a + 12) and (b, 3/2b + 12)

rise = (3/2b + 12) - (3/2a + 12)

run = b - a

slope = [3/2b+ 12) - (3/2a+12)] / b - a

= (3/2 b - 3/2a)/ b - a

= 3/2 (b - a) / b - a

= 3/2

confidence rating #$&*:

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Self-critique rating:

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Self-critique rating:

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