#$&*
course Mth 163
10/10 230
http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm
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Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.
009.
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Question: `q001. Note that this assignment has 2 questions
For the function y = 1.1 x + .8, what are the coordinates of the x = x1 point, in terms of the symbol x1? What are the coordinates of the x = x2 point, in terms of the symbol x2?
What therefore is the rise between these two points, and what is the run?
What is the average slope of the graph between these two points? Be sure to simplify your result.
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Your solution:
(x1, 1.1x + .8 y1) and (x2, 1.1x + .8 y2)
Rise = (1.1x+8 y2) - (1.1x + .8 y1)
Run = (x2 - x1)
Slope = (1.1x + .8 y2) - (1.1x + .8 y1) / (x2 - x1)
Simplified = (1.1x y2) - (1.1x y1) / (x2 - x1)
confidence rating #$&*: 3
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Given Solution:
In terms of the symbol x1 the coordinates of the x = x1 point are ( x1, 1.1 x1 + .8) and the coordinates of the x = x2 point are ( x2, 1.1 x2 + .8).
The rise between the two points is therefore
rise = (1.1 x2 + .8) - (1.1 x1 + .8) = 1.1 x2 + .8 - 1.1 x1 - .8 = 1.1 x2 - 1.1 x1.
The run is
run = x2 - x1.
The slope is therefore (1.1 x2 - 1.1 x1) / (x2 - x1) = 1.1 (x2 - x1) / (x2 - x1) = 1.1.
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Self-critique (if necessary):
I’m not sure I understand why there wouldn’t be a y1 and y2. You have on both sides, x2 and x1 for the x and y coordinates. I’m a little confused on this. I thought it would be (y2 - y1) / (x2 - x1). So therefore it would come out how I originally had it. (not sure if I simplified my version correctly). Could you help me?????
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Self-critique rating: ok
@&
You are given the means to find y1 and y2 from the values of x1 and x2.
Everything can, and should, be done in terms of the symbols x1 and x2.
*@
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Question: `q002. For the function y = 3.4 x + 7, what are the coordinates of the x = x1 point, in terms of the symbol x1? What are the coordinates of the x = x2 point, in terms of the symbol x2?
What therefore is the rise between these two points, and what is the run?
What is the average slope of the graph between these two points? Be sure to simplify your result.
YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
Your solution:
( I am going to work this one the same way you did the last one, for my notes, in case I am wrong on the previous question.)
(x1, 3.4x1 + 7)
(x2, 3.4x2 + 7)
Rise = (3.4x2 - 7) - (3.4x1 + 7)
Run = (x2 - x1)
Slope = (3.4x2 + 7) - (3.4x1 + 7) / (x2 - x1)
= (3.4x2) - (3.4x1) / (x2 - x1)
= 3.4 (x2 - x1) / (x2 - x1)
confidence rating #$&*: 3
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution:
In terms of the symbol x1 the coordinates of the x = x1 point are ( x1, 3.4 x1 + 7) and the coordinates of the x = x2 point are ( x2, 3.4 x2 + 7).
The rise between the two points is therefore
rise = (3.4 x2 + 7) - (3.4 x1 + 7) = 3.4 x2 + 7 - 3.4 x1 - 7 = 3.4 x2 - 3.4 x1.
The run is
run = x2 - x1.
The slope is therefore (3.4 x2 - 3.4 x1) / (x2 - x1) = 3.4 (x2 - x1) / (x2 - x1) = 3.4.
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Self-critique (if necessary):
I am understanding this better now. I have corrected the first problem in my notes.
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Self-critique rating:
@&
I expected that you would catch on.
*@
ok
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Self-critique (if necessary):
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Self-critique rating:
ok
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Self-critique (if necessary):
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Self-critique rating:
#*&!
&#Good responses. See my notes and let me know if you have questions. &#