Asst 13 qa

#$&*

course Mth 163

10/27 3

013.

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Question: `q001. Note that this assignment has 14 questions

What does 2^5 mean?

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Your solution:

2^5 means 2 to the power of 5 which means 2*2*2*2*2 = 32

confidence rating #$&*: 3

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Given Solution:

2^5 stands for 2 raised to the fifth power; i.e., 2^5 = 2*2*2*2*2.

The result of this calculation is 2^5 = 32.

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Question: `q002. What does 2^3 * 2^5 mean? Is the result of power of 2? If so, what power of 2 is it?

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Your solution:

2^3 means 2 to the power of 3 times 2^5 which is 2 to the power of 5. You would add the power exponents together to give you 2^8 which is 256.

confidence rating #$&*: 3

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Given Solution:

2^3 * 2^5 means (2*2*2) * (2*2*2*2*2). This is the same as 2*2*2*2*2*2*2*2, or 2^8.

When we multiply this number out, we obtain 256.

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Question: `q003. Why do we say that a^b * a^c = a^(b+c)?

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Your solution:

Because when multiplying numbers with exponents, you would add the exponents and then a^(b+c) would be the answer.

confidence rating #$&*: 3

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Given Solution:

We saw in the preceding example that 2^3 * 2^5 stood for a product of three 2's, multiply by a product of five 2's. We saw also that the result was identical to a product of eight 2's. This was one instance of the general rule that when we multiply to different powers of the same number, the result is that number raised to the sum of the two powers.

One general way to state this rule is to let a stand for the number that is being raised to the different powers, and let b and c stand for those powers. Then we get the statement a^b * a^c = a^(b+c).

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Question: `q004. What does (2^3)^5 mean?

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Your solution:

For this one, you would multiply the exponents since there is a ( ) involved. So the answer would be

(2^3)^5

2^15 = 32768

confidence rating #$&*: 3

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Given Solution:

Since 2^3 stands for 2*2*2, it follows that (2^3)^5 means (2^3)*(2^3)*(2^3)*(2^3)*(2^3) = (2*2*2)*(2*2*2)*(2*2*2)*(2*2*2)*(2*2*2) = 2*2*2*2*2*2*2*2*2*2*2*2*2*2*2 = 2^15.

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Question: `q005. Why do we say that (a^b)^c = a^(b*c)?

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Your solution:

Because when you have a parentheses you would multiply the exponents instead of adding them. So then you would have a^(b*c)

confidence rating #$&*: 3

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Given Solution:

We saw in the last example how (2^3)^5 stands for the product of 5 quantities, each equal to the product of three 2's. We saw how this is equivalent to the product of fifteen 2's, and we saw how the fifteen was obtained by multiplying the exponents 3 and 5.

In the present question a^b stands for the quantity a multiplied by itself b times. (a^b)^c stands for the quantity a^b multiplied by itself c times, which is equivalent to multiplying a by itself b * c times. Thus we say that (a^b)^c = a^(b * c).

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Question: `q006. According to the law a^b * a^c = a*(b+c), if we multiply 2^5 by 2^-2 what power of 2 should we get?

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Your solution:

For 2^5 * 2^-2 you would get

2^(5+-2) which would be 2^3

confidence rating #$&*: 3

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Given Solution:

According to the law, 2^5 * 2^-2 = 2^(5 + -2) = 2^(5-2) = 2^3.

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Question: `q007. Since as we saw in the preceding question 2^5 * 2^-2 = 2^3, what therefore must be the value of 2^-2?

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Your solution:

The value of 2^-2 would be 1 / 2^2.

confidence rating #$&*: 3

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Given Solution:

One way of seeing this is to note that 2^5 = 32 and 2^3 = 8, so we have 32 * 2^-2 = 8. Dividing both sides by 32 we get 2^-2 = 8 / 32 = 1/4.

We can learn something important if we keep the calculation in powers of 2. If 2^5 * 2^-2 = 2^3, then dividing both sides of the equation by 2^5 we obtain 2^-2 = 2^3/2^5, which is equal to 1/2^2.

This shows us why 2^-2 = 1/2^2.

QUESTIONABLE STUDENT RESPONSE: .25

INSTRUCTOR COMMENT

.25 is of course the value of 2^-2. However I'm not sure you've connected this with the fact that 2^5 * 2^-2 = 2^3, as was the intent of the question.

A key word in the given question is 'therefore', which asks you to connect your answer to the fact that 2^5 * 2^-2 = 2^3.

STUDENT QUESTION

It seems to me to be a lot more work to calculate 2^-2 in the process of solving 32 * 2^-2 = 8 but I understand why it can

also be done this way. I am just not sure I understand the need to see it this way. I guess I will understand “why” we need

to know this in future problems.

INSTRUCTOR RESPONSE

The distinction is between using a rule and understanding the reason for the rule.

The rule is that a^(-b) = 1 / a^b, so of course it's valid to say that 2^-2 = 1 / 2^2 = 1/4.

However just applying the rule doesn't give any insight into why the rule must be as it is.

The reason this has to be the rule is that if it isn't, then the calculation of this problem and others like it make no sense. If the other laws of exponents are to be consistent, a^(-b) must by 1 / a^b, as demonstrated by this example.

STUDENT QUESTION

I just don’t understand this part of our assignments. I went back to the CD to see if I could understand it further, but I

can’t seem to find the section. Is there a chapter in our book that would help me to better understand this?

INSTRUCTOR RESPONSE

We're trying to show why 2^(-n) = 1 / 2^n.

Think of it this way:

Suppose you have the expression, say, 2^3 / 2^7. We can look at this expression in two ways:

2^3 / 2^7, which by the laws of exponents must be 2^(3 - 7) = 2^(-4). Let's suppose we don't know what 2^(-4) means. We can

find out by looking at our original expression in another way:

2^3 / 2^7 = (2 * 2 * 2) / (2 * 2 * 2 * 2 * 2 * 2 * 2) = 1 / (2 * 2 * 2 * 2) = 1 / 2^4.

So now we have two ways of writing 2^3 / 2^7. One way is 2^(-4), the other way is 1 / 2^4.

We conclude that 2^(-4) = 1 / 2^4.

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Question: `q008. Why must we say that 2^-n = 1 / 2^n, where n stands for any counting number?

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Your solution:

We say that because when you multiply 2^-n by another number you could get

2^x * 2^-n which would be 2^(x-n). Whichever way you multiply them, you will come up with the same answer as to 1 / 2^n or 2^-n.

confidence rating #$&*: 3

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Given Solution:

This is because for any number m, we have 2^m * 2^-n = 2^( m + -n) = 2^(m-n), and we also have 2^m * (1 / 2^n) = 2^m / 2^n = 2^(m-n). So whether we multiply 2^m by 2^-n or by 1 / 2^n we get the same result. This shows that 2^-n and 1 / 2^n are the same.

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Question: `q009. According to the law a^b * a^c = a^(b+c), if we multiply 2^3 by 2^-3 what power of 2 should we get?

Since 2^-3 = 1 / 2^3, what number must we get when we multiply 2^3 by 2^-3?

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Your solution:

If you multiply them you would get 2 ^(3-3) = 2^0 which is 1.

If you multiply in a way of 2^3 * 2^-3 = 8 * 1/ 2^3 = 8 * 1/8 = 1.

Either way, you will get 1.

confidence rating #$&*: 3

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Given Solution:

2^3 * 2^-3 = 2^(3 + -3) = 2^(3-3) = 2^0.

Since 2^-3 = 1 / 2^3 it follows that 2^3 * 2^-3 = 2^3 * ( 1 / 2^3) = 1.

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Question: `q010. Continuing the last question, what therefore should be the value of 2^0?

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Your solution:

2 ^ 0 would be 1.

confidence rating #$&*: 3

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Given Solution:

Since 2^3 * 2^-3 = 2^0 and also 2^3 * 2^-3 = 1 we see that 2^0 must be 1.

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Question: `q011. How do we solve the equation x^3 = 12?

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Your solution:

x^3 = 12

You would multiply (1/3) to each side of exponent and do x^(3*1/3) and 12 ^(1/3) which would be x = 2.289

confidence rating #$&*: 3

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Given Solution:

We solve the equation by taking the 1/3 power of both sides:

(x^3)^(1/3) = 12^(1/3), then by the law (a^b)^c = a^(bc) we have

x^(3 * 1/3) = 12^(1/3), so that

x^1 = 12^(1/3) or just

x = 12^(1/3), which we can easily enough evaluate with a calculator. We obtain a result of approximately x = 2.29 .

STUDENT QUESTION

I see in the solution you raise each side to a power of 1/3. Is it also okay to just take the cube root of each side, since

that is equivalent?

INSTRUCTOR RESPONSE: It's easier to denote fractional exponents using the keyboard than to denote radicals, which is the reason fractional exponents are used in these solutions.

You should be able to do it either way, if requested.

However either way is fine, and your solution is good.

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Question: `q012. How do we solve the equation x^(5/2) = 44?

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Your solution:

You would multiply the exponent by 2/5.

x^(5/2 * 2/5) = 44^(2/5)

x = 4.54

confidence rating #$&*: 3

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Given Solution:

If we take the 2/5 power of both sides we get

(x^(5/2))^(2/5) = 44^(2/5) or

x^(5/2 * 2/5) = 44^(2/5) or

x^1 = 44^(2/5) so that

x = 44^(2/5).

Evaluating by calculator you should obtain approximately x = 4.54.

STUDENT COMMENT

Okay, I see now why in question 11, you multiplied each side of the equation by 1/3 to get rid of the power of 3 attached to

x. In this problem it would be more difficult to take a 5/2 root of a number. It is much easier to just flip that fraction

and raise both sides to that power. (5/2) * (2/5) equals 1, so you wind up with x^1 on one side, which is just x and multiply

the other side by 2/5 to get the result of x.

INSTRUCTOR RESPONSE

You could equally well write this as the 5th root of x^2, or even as the square of the 5th root of x, but the fractional

notation is more compact, less cumbersome, in a text-based medium.

The fractional notation also makes more sense of the calculation, for the reasons you have noted.

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If you understand the assignment and were able to solve the previously given problems from your worksheets, you should be able to complete most of the following problems quickly and easily. If you experience difficulty with some of these problems, you will be given notes and we will work to resolve difficulties.

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Question: `q013. In terms of the meaning of 5^7, the meaning of 5^4 and the meaning of 5^11, explain why 5^7 * 5^4 = 5^11. We both know that the rule for multiplying these numbers tells us that 5^7 *5^4 = 5^(7 + 4). You can't explain by quoting this rule, or any rule; you need to explain in terms of the given meanings.

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Your solution:

confidence rating #$&*:

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Question: `q014. Explain in terms of the rule a^b * a^c = a^(b + c) why 7^-11 must be equal to 1 / (7^11).

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Your solution:

7^-11 must be equal to 1/7^11 because whether you multiply 7^-11 or 1/7^11 you will get the same result.

confidence rating #$&*: 3

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Question: Solve the equation 2 x * 5^(-3/5) = 9, giving an exact solution (which will be expressed in terms of rational numbers and powers of rational numbers; for example 17^(43/11) / 8 is expressed in this manner but its approximate value 8069.501481 is not exact).

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Your solution:

2x * 5^(-3/5) = 9

10x^(2/5) = 9

10x(2/5*5/2) = 9^(5/2)

10x = 243

X = 24.3

confidence rating #$&*: 2?

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Self-critique rating:

Ok, im not sure if I got the order of operations on this correct, but according to the previous exercises, I think I have this right. If not, please correct me and I will update my notes. Thank you *****

"

Your solution, with inserted notes:

2x * 5^(-3/5) = 9

10x^(2/5) = 9

@&

5 is preceded by * and followed by ^.

^ takes precedence over *, so you cannot multiply the 2x by the 5 before you raise 5 to the -3/5 power.

It appears that you might have done this, though there is another possible explanation for this step.

*@

@&

You might have intended to multiply the left-hand side by 5. Since 5 * 5^(-3/5) = 5^(1 - 3/5) = 5^(2/5), this operation would give you 5^(2/5).

However having multiplied 5^(-3/5) by 5, you would not also multiply the 2x by 5. And you would still have 5^(2/5) in your expression.

Also, having multiplied the left-hand side by 5 you would need to do the same to the right-hand side.

*@

@&

In any case x is not and never was raised to the 2/5 power. The only factor that is exponentiated is the 5.

*@

10x(2/5*5/2) = 9^(5/2)

@&

If the equation was 10 x^(2/5) = 9, then raising both sides to the 5/2 power would give you

( 10 x^(2/5) ) ^ (5/2) = 9^(5/2)

The left-hand side would be simplified as

10^(2/5) * ( x^(2/5) )^(5/2),

which equals

10^(2/5) * x^(2/5 * 5/2), and hence is equal to

10^(2/5) * x.

The equation would become

10^(2/5) x = 9^(5/2).

To find x you would multiply both sides by 10^(-2/5) to ge

x = 9^(5/2) * 10^(-2/5).

However this would be the result if the original equation was equivalent to 10 x^(2/5) = 9, which is not the case.

*@

10x = 243

X = 24.3

@&

To correctly solve the equation

2x * 5^(-3/5) = 9

you would isolate x. You could do so in one of at least two ways.

Dividing both sides by 2 * 5^(-3/5) you would get

x = 9 / (2 * 5^(-3/5) ),

which you would simplify to

x = 9/2 * 5^(3/5).

Note that 1 / 5^(-3/5) = 1 / (1 / 5^(3/5) ) = 1 * 5^(3/5) / 1 = 5^(3/5).

Another way would be to first express everything with positive exponents:

2 x * 1 / (5^(3/5) ) = 9.

Then divide both sides by 2 to get

x * 1 / (5 ^(3/5) ) = 9/2

and finally multiply by 5^(3/5) to get

x = 9/2 * 5^(3/5).

*@

Self-critique (if necessary):

------------------------------------------------

Self-critique rating:

Ok, im not sure if I got the order of operations on this correct, but according to the previous exercises, I think I have this right. If not, please correct me and I will update my notes. Thank you *****

"

Your solution, with inserted notes:

2x * 5^(-3/5) = 9

10x^(2/5) = 9

@&

5 is preceded by * and followed by ^.

^ takes precedence over *, so you cannot multiply the 2x by the 5 before you raise 5 to the -3/5 power.

It appears that you might have done this, though there is another possible explanation for this step.

*@

@&

You might have intended to multiply the left-hand side by 5. Since 5 * 5^(-3/5) = 5^(1 - 3/5) = 5^(2/5), this operation would give you 5^(2/5).

However having multiplied 5^(-3/5) by 5, you would not also multiply the 2x by 5. And you would still have 5^(2/5) in your expression.

Also, having multiplied the left-hand side by 5 you would need to do the same to the right-hand side.

*@

@&

In any case x is not and never was raised to the 2/5 power. The only factor that is exponentiated is the 5.

*@

10x(2/5*5/2) = 9^(5/2)

@&

If the equation was 10 x^(2/5) = 9, then raising both sides to the 5/2 power would give you

( 10 x^(2/5) ) ^ (5/2) = 9^(5/2)

The left-hand side would be simplified as

10^(2/5) * ( x^(2/5) )^(5/2),

which equals

10^(2/5) * x^(2/5 * 5/2), and hence is equal to

10^(2/5) * x.

The equation would become

10^(2/5) x = 9^(5/2).

To find x you would multiply both sides by 10^(-2/5) to ge

x = 9^(5/2) * 10^(-2/5).

However this would be the result if the original equation was equivalent to 10 x^(2/5) = 9, which is not the case.

*@

10x = 243

X = 24.3

@&

To correctly solve the equation

2x * 5^(-3/5) = 9

you would isolate x. You could do so in one of at least two ways.

Dividing both sides by 2 * 5^(-3/5) you would get

x = 9 / (2 * 5^(-3/5) ),

which you would simplify to

x = 9/2 * 5^(3/5).

Note that 1 / 5^(-3/5) = 1 / (1 / 5^(3/5) ) = 1 * 5^(3/5) / 1 = 5^(3/5).

Another way would be to first express everything with positive exponents:

2 x * 1 / (5^(3/5) ) = 9.

Then divide both sides by 2 to get

x * 1 / (5 ^(3/5) ) = 9/2

and finally multiply by 5^(3/5) to get

x = 9/2 * 5^(3/5).

*@

Self-critique (if necessary):

------------------------------------------------

Self-critique rating:

#*&!

Ok, im not sure if I got the order of operations on this correct, but according to the previous exercises, I think I have this right. If not, please correct me and I will update my notes. Thank you *****

"

Your solution, with inserted notes:

2x * 5^(-3/5) = 9

10x^(2/5) = 9

@&

5 is preceded by * and followed by ^.

^ takes precedence over *, so you cannot multiply the 2x by the 5 before you raise 5 to the -3/5 power.

It appears that you might have done this, though there is another possible explanation for this step.

*@

@&

You might have intended to multiply the left-hand side by 5. Since 5 * 5^(-3/5) = 5^(1 - 3/5) = 5^(2/5), this operation would give you 5^(2/5).

However having multiplied 5^(-3/5) by 5, you would not also multiply the 2x by 5. And you would still have 5^(2/5) in your expression.

Also, having multiplied the left-hand side by 5 you would need to do the same to the right-hand side.

*@

@&

In any case x is not and never was raised to the 2/5 power. The only factor that is exponentiated is the 5.

*@

10x(2/5*5/2) = 9^(5/2)

@&

If the equation was 10 x^(2/5) = 9, then raising both sides to the 5/2 power would give you

( 10 x^(2/5) ) ^ (5/2) = 9^(5/2)

The left-hand side would be simplified as

10^(2/5) * ( x^(2/5) )^(5/2),

which equals

10^(2/5) * x^(2/5 * 5/2), and hence is equal to

10^(2/5) * x.

The equation would become

10^(2/5) x = 9^(5/2).

To find x you would multiply both sides by 10^(-2/5) to ge

x = 9^(5/2) * 10^(-2/5).

However this would be the result if the original equation was equivalent to 10 x^(2/5) = 9, which is not the case.

*@

10x = 243

X = 24.3

@&

To correctly solve the equation

2x * 5^(-3/5) = 9

you would isolate x. You could do so in one of at least two ways.

Dividing both sides by 2 * 5^(-3/5) you would get

x = 9 / (2 * 5^(-3/5) ),

which you would simplify to

x = 9/2 * 5^(3/5).

Note that 1 / 5^(-3/5) = 1 / (1 / 5^(3/5) ) = 1 * 5^(3/5) / 1 = 5^(3/5).

Another way would be to first express everything with positive exponents:

2 x * 1 / (5^(3/5) ) = 9.

Then divide both sides by 2 to get

x * 1 / (5 ^(3/5) ) = 9/2

and finally multiply by 5^(3/5) to get

x = 9/2 * 5^(3/5).

*@

Self-critique (if necessary):

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Self-critique rating:

#*&!#*&!

&#Your work looks good. See my notes. Let me know if you have any questions. &#