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phy121
Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_04.1_labelMessages **
The problem:
A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds.
• Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s).
• Sketch a straight line segment between these points.
• What are the rise, run and slope of this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Rise= 40cm/s-10cm/s
Rise= 30cm/s
Run= 9s-4s
Run= 5s
Slope= rise/run
Slope= 30cm/s /5s
Slope= 6cm/s^2
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• What is the area of the graph beneath this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Area of rectangle= l*w
5*10= 50
Area of triangle= 0.5*b*h
0.5*5*30= 75
Combine: 50+75= 125cm^2
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Think of this as a trapezoid.
There is insight to be gained by interpreting the triangle and the rectangle, but the easiest and most basic idea is interpreted by the trapezoid.
Note that the lengths and widths have units, and the units do not multiply out to cm^2.
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5 minutes
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I used a different way to calculate the area. I make it into 2 shapes, found the area for both the shapes then added their areas together to get the overall area.
&#Good responses. See my notes and let me know if you have questions. &#