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phy121
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_07.2_labelMessages **
An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
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`ds = v0 `dt + .5 a `dt^2
a = 2 `ds / `dt^2
Trial 1
a= 2*10m/8s^2
a= 20m/64s
a= 0.3125m/s^2
Trial 2
A= 2*10m/5s^2
A= 20m/25s
A= 0.8m/s^2
On a acceleration vs incline graph, where acceleration is on the Y-axis and the incline is on the X-axis, the slope would be rise/run, therefore:
0.8m/s^2-0.3125m/s^2= 0.4875m/s^2 (rise)
0.1-0.05= 0.05 (run)
0.4875m/s^2/0.05= 9.75m/s^2
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Great.
This result should (and in fact does) give you, within experimental uncertainty, the acceleration of gravity.
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10 minutes
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&#Very good responses. Let me know if you have questions. &#