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phy121
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_11.1_labelMessages **
Answer the following based on Newton's Second Law:
• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
F= m*a
F= 12kg*3m/s^2
F= 36N
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• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
A= F/m
A= 20N/4kg
A= 5m/s^2
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• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
If you find the acceleration of the object when you pushed it at 20N and weighed 10kg, the acceleration would be:
A= 20N/10kg
A= 2m/s^2.
But the acceleration in the direction of the force says 1.5m/s^2, therefore we know there is an opposing force on the object.
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• What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> :
In the positive the force is 20N. However, if you take the acceleration that it was moving (not the calculated one) and multiply it by the weight of the cart:
F= 1.5m/s^2*10kg
F= 15N
Therefore, the net force is:
Fnet= +20N-15N= +5N in the positive direction.
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&#Very good responses. Let me know if you have questions. &#