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phy121
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_12.1_labelMessages **
Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
5kg*9.8N= 49N
6kg*9.8N= 58.8N
Since there is no friction, the Fnet= 58.8N-49N= 9.8N
A= Fnet/m
A= 9.8N/11kg
A= 0.89m/s^2 in the direction of he 6kg weight.
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• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
if mass is descending then its velocity is -1.8m/s
‘dv= a*’dt
‘dv= 0.89m/s^2*1s= 0.89m/s
Vf= v0+’dv
Vf= -1.8m/s + 0.89m/s
‘dv= -0.91m/s
The mass will be descending at 0.91m/s
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• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
During the 1s interval, the acceleration is positive while the velocity is negative. So they are in opposite directions, which means the object is slowing down. As time passes, the masses will be at rest for a second before both a and v is positive thus meaning speeding up.
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&#Your work looks very good. Let me know if you have any questions. &#