#$&*
phy121
Your 'cq_1_19.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_19.2_labelMessages **
Sketch a vector representing a 10 Newton force which acts vertically downward.
• Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.
answer/question/discussion: ->->->->->->->->->->->-> :
After sketching the graph, I would need to rotate it 20 degrees counterclockwise for the vector to be pointing straight in the vertical downward direction.
#$&*
• What are the x and y components of the equilibrant of the force?
answer/question/discussion: ->->->->->->->->->->->-> :
X= 10N*cos(250)= -3.4N
Y= 10N*sin(250)= -9.4N
#$&*
@&
Those are the components of the force. The components of the equilibrant will be equal and opposite to these.
*@
*#&!*#&!
Good responses. See my notes and let me know if you have questions.