#$&*
phy121
Your 'cq_1_19.3' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
An object moving in the direction 120 degrees (as measured counterclockwise to the positive x axis) encounters a net force whose direction is 270 degrees.
• Sketch the force and its component along the line of motion, as well as its component perpendicular to the line of motion.
answer/question/discussion: ->->->->->->->->->->->-> :
The vector is at 120 degrees, so it is in the second quadrant by going counterclockwise. The force vector is on the Y axis on the negative side.
#$&*
• Suppose you are facing in the direction of motion. Do you perceive the component of the force along the line of motion to be forward or backward? It this component in the direction of motion or opposite to the direction of motion?
answer/question/discussion: ->->->->->->->->->->->-> :
If facing the direction of motion, you would have to turn 150 degrees to face the direction of the force. If in the opposite direction, turn 30 degrees. Since it is closer in the opposite direction, the force along the line is opposite to the direction of the motion.
#$&*
• Will the object speed up, slow down or maintain a constant speed?
answer/question/discussion: ->->->->->->->->->->->-> :
The object will slow down.
#$&*
• If you are facing in the direction of motion, then the line perpendicular to the direction of motion will run to your right and to your left. Is the component of the force perpendicular to the line of motion directed to the right or to the left?
answer/question/discussion: ->->->->->->->->->->->-> :
The component is moving towards the left direction.
#$&*
• Will the object veer to the right, to the left or maintain straight-line motion?
answer/question/discussion: ->->->->->->->->->->->-> :
the force vector has a left component so it will veer left.
#$&*
• Which is greater in magnitude, the component of the force along the line of motion or the component perpendicular to the line of motion?
answer/question/discussion: ->->->->->->->->->->->-> :
the two vectors equal: 270-120= 150degrees. Which makes it 30 degrees from the parallel, so the perpendicular would be 60 degrees. The parallel direction is greater than the perpendicular direction.
#$&*
*#&!
&#Very good responses. Let me know if you have questions. &#