cq_1_61

Phy231

Your 'cq_1_6.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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For each situation state which of the five quantities v0, vf, `ds, `dt and a are given, and give the value of each.

• A ball accelerates uniformly from 10 cm/s to 20 cm/s while traveling 45 cm.

answer/question/discussion:

v0=10cm/s

vf=20cm/s

`ds=45cm

vAve=(10cm/s+20cm/s)/2=15cm/s

`dt=45cm/15cm/s=3s

a=(20cm/s-10cm/s)/3s=3.3cm/s^2

• A ball accelerates uniformly at 10 cm/s^2 for 3 seconds, and at the end of this interval is moving at 50 cm/s.

answer/question/discussion:

a=10cm/s^2

`dt=3s

vf=50cm/s

v0=50cm/s-(10cm/s^2*3s)=20cm/s

vAve=(50cm/s+20cm/s)/2=35cm/s

`ds=35cm/s*3s=105cm

• A ball travels 30 cm along an incline, starting from rest, while accelerating at 20 cm/s^2.

answer/question/discussion:

`ds=30cm

a=20cm/s^2

v0=0

vf=sqrt(v0^2+2a`ds)=sqrt(0^2+2(20cm/s^2)(30cm))=sqrt(1200cm^2/s^2)=34.6cm/s

vAve=(0cm/s+34.6cm/s)/2=17.3cm/s

`dt=30cm/17.3cm/s=1.73s

Then for each situation answer the following:

• Is it possible from this information to directly determine vAve?

answer/question/discussion:

Yes see above

• Is it possible to directly determine `dv?

answer/question/discussion:

Yes simply subtract v0 from vf.

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20 minutes

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&#Very good responses. Let me know if you have questions. &#