Phy231
Your 'cq_1_7.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion:
slope=.05
`ds=10m
`dt=8s
v0=0
vAve=10m/8s=1.25m/s
vf=2*1.25m/s=2.5m/s
a=2.5m/s/8s=0.3125m/s^2
slope=.1
`dt=5s
`ds=10m
V0=0
vAve=10m/5s=2m/s
vf=2*2m/s=4m/s
a=4m/s/5s=0.8m/s^2
average rate of change in acceleration vs change in slope of incline:
=(a2-a1)(m/s^2)/(s2-s1)(units)
=(0.8m/s^2-0.3125m/s^2)/(0.1units-0.05units)
=0.4875m/s^2/0.05units
=9.75m/s^2/unit
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30 minutes
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