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Phy 121
Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
8cm/s^2*3s=24cm/s 24cm/s+12cm/s=36cm/s
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Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
vAve=(v0-vf)/2
(12cm/s-36cm/s)/2=12cm/s
@& Your calculation would give you - 12 cm/s.
However you don't average two quantities by subtracting them and dividing by 2. You add them and divide by 2.*@
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How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
vAve*'dt='ds
(12cm/s)*3s=36cm
@& This will work when you have the correct average velocity.
*@
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Copy and paste your work into the box below and submit as indicated:
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30min
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@& The initial velocity of the object is 12 cm/s, and it speeds up. Your average velocity result is not consistent with this.
See my note.
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Be sure to include the entire document, including my notes.
If my notes indicate that revision is optional, use your own judgement as to whether a revision will benefit you. &#
*@