#$&*
Phy 121
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds,
starting from rest. The same automobile requires 5 seconds to roll the same
distance down an incline with slope .10, again starting from rest.
At what average rate is the automobile's acceleration changing with respect to the
slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
.05 slope vAve='ds/'dt=10m/8s=1.25m/s^2
.10 slope vAve='ds/'dt=10m/5s=2m/s^2
#$&*
@& 10 m / 8 s = 1.25 m/s, not 1.25 m/s^2, and this is an average velocity, not an acceleration.*@
*#&!*#&!
@& Please calculate the acceleration for each trial, then complete the rest of the question. You're welcome to ask additional questions if necessary.
When you resubmit, be sure you have included the entire 'seed' question. There are additional question that aren't included here.
*@