cq_1_072

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Phy 121

Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** CQ_1_07.2_labelMessages **

An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.

• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?

answer/question/discussion: ->->->->->->->->->->->-> :

Slope 1:

‘ds = 10m

‘dt = 8s

vAve = 10m /8s = 1.25m/s

vf = 2 * 1.25m/s = 2.5m/s

aAve = 2.5m/s / 8s = .31m/s^2

Slope 2:

‘ds = 10m

‘dt = 5s

vAve = 10m /5s = 2m/s

vf = 2 * 2m/s = 4m/s

aAve = 4m/s / 5s = .8m/s^2

Average rate of change of acceleration with respect to ramp slope:

ave rate = change is acceleration / change in ramp slope

ave rate = (.8m/s^2 - .31m/s^2) / (.10 - .05)

ave rate = (.49m/s^2) / (.05)

ave rate = 9.8m/s^2

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30 min

&#Very good responses. Let me know if you have questions. &#