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Phy 121
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_07.2_labelMessages **
An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
Slope 1:
‘ds = 10m
‘dt = 8s
vAve = 10m /8s = 1.25m/s
vf = 2 * 1.25m/s = 2.5m/s
aAve = 2.5m/s / 8s = .31m/s^2
Slope 2:
‘ds = 10m
‘dt = 5s
vAve = 10m /5s = 2m/s
vf = 2 * 2m/s = 4m/s
aAve = 4m/s / 5s = .8m/s^2
Average rate of change of acceleration with respect to ramp slope:
ave rate = change is acceleration / change in ramp slope
ave rate = (.8m/s^2 - .31m/s^2) / (.10 - .05)
ave rate = (.49m/s^2) / (.05)
ave rate = 9.8m/s^2
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30 min
Very good responses. Let me know if you have questions.