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Phy 121
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_11.1_labelMessages **
Answer the following based on Newton's Second Law:
• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
f=m*a
f=12kg*3m/s^2
f=36Newtons
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• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
f=m*a
20N=4kg*a
A=20N/4kg
A=5m/s^2
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• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
f=m*a
20N=10kg*a
A=20N/10kg
A=2m/s^2
So the 1.5m/s^2 that we were given has to be opposing force
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• What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> :
F=m*a
F=10kg*1.5m/s^2
F=15N
Fnet=20N-15N
Fnet=5N
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*#&!
&#Good responses. Let me know if you have questions. &#