#$&*
Phy 241
Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.
What is your best guess about the ball's average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
#$&* The average velocity is (10cm/sec - 4cm/s)/2 = 6cm/sec
@& 6 cm/s is closer to 4 cm/s than to 10 cm/s.
You would never subtract two quantities and divide by 2 to get their average.
Also (10 - 4) / 2 is 3, not 6.*@
Without further information, why is this just a guess?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
#$&*
If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
#$&* we know that average velocity = change in position /change in time , so the change in position = average velocity*change in time.
At what average rate did its velocity change with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
#$&* The average rate at which the velocity changes with respect to clock time is called the average acceleration.
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It took about 30 minutes.
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&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
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