#$&*
Phy 241
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The problem:
A ball starts with velocity 0 and accelerates uniformly down a ramp of length 30 cm, covering the distance in 5 seconds.
What is its average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
#$&* Its average velocity is = 30cm/5sec = 6 cm/sec
If the acceleration of the ball is uniform then its average velocity is equal to the average of its initial and final velocities.
You know its average velocity, and you know the initial velocity is zero.
What therefore must be the final velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
#$&* If the initial velocity is zero then the final velocity will be:
We know that average velocity = (final velocity - initial velocity)/2, so final velocity = average velocity*2 = 6cm/sec*2 = 12cm/sec
By how much did its velocity therefore change?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
#$&* Its velocity doubled.
At what average rate did its velocity change with respect to clock time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
#$&* The average rate = change in velocity/change of clock time = 6cm/sec/5sec = 1.2cm/sec^2
@& 6 cm/s is the average velocity, not the change in velocity.*@
What would a graph of its velocity vs. clock time look like? Give the best description you can.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
#$&* The graph of velocity vs clock time where the velocity increases from 0m/s to 12m/s in 5 sec with constant rate of change will be a linear graph.
@& This is a good description.*@
*#&!*#&!
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Solution
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