cq_1_041

#$&*

Phy 241

Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** **

The problem:

A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds. 

Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s). 

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): 

 

#$&* The velocity will be on the vertical axis while the clock time will be on the horizontal axis. We will use the slope between the two events to get the acceleration.

Sketch a straight line segment between these points. 

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): 

 

#$&* When we sketch a straight line it implies a constant acceleration.

What are the rise, run and slope of this segment? 

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): 

 

#$&*The slope = rise / run. Rise is the change in velocity. The run is the change in clock time.

What is the area of the graph beneath this segment?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): 

 

#$&*Area = ave.ht * width = 40 cm/s * 9 sec = 360 cm

@& The trapezoid formed by the two points has width representing 5 seconds, not 9 seconds.

The maximum 'graph altitude' represents 40 cm/s. The average 'graph altitude' is significantly less than this.*@

*#&!*#&!

@& You should submit a revision. Be sure you understand everything.

&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.

Then please compare your old and new solutions with the expanded discussion at the link

Solution

Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.

If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#

*@

cq_1_041

#$&*

Phy 241

Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** **

The problem:

A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds. 

Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s). 

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): 

 

#$&* The velocity will be on the vertical axis while the clock time will be on the horizontal axis. We will use the slope between the two events to get the acceleration.

Sketch a straight line segment between these points. 

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): 

 

#$&* When we sketch a straight line it implies a constant acceleration.

What are the rise, run and slope of this segment? 

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): 

 

#$&*The slope = rise / run. Rise is the change in velocity. The run is the change in clock time.

What is the area of the graph beneath this segment?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): 

 

#$&*Area = ave.ht * width = 40 cm/s * 9 sec = 360 cm

@& The trapezoid formed by the two points has width representing 5 seconds, not 9 seconds.

The maximum 'graph altitude' represents 40 cm/s. The average 'graph altitude' is significantly less than this.*@

*#&!*#&!

@& You should submit a revision. Be sure you understand everything.

&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.

Then please compare your old and new solutions with the expanded discussion at the link

Solution

Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.

If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#

*@