phy 201
Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> : If the initial velocity is 12cm/se and the ball moves for 3sec, accelerating by 8cm each second, then the final velocity would be 36cm/sec. I found this by multiplying 8cm/sec^2(3seconds) which gave 24cm/sec. I then added this to the initial speed of 12cm/sec.
• Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> : If we assume constant or uniform acceleration, we find average velocity by adding the two velocities and dividing by two. This would be (36cm/sec+12cm/sec)/2 which gives an average velocity of 24cm/sec.
• How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> : To find the distance traveled, you take average velocity and multiply it by the time interval. This would be 3sec(24cm/sec). The second units will cancel out leaving us with 72cm.
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10 minutes
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&#This looks very good. Let me know if you have any questions. &#