Phy 201
Your 'cq_1_8.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
A ball is tossed upward at 15 meters / second from a height of 12 meters above the ground. Assume a uniform downward acceleration of 10 m/s^2 (an approximation within 2% of the 9.8 m/s^2 acceleration of gravity).
How high does it rise and how long does it take to get to its highest point?
How fast is it then going when it hits the ground, and how long after the initial toss does it first strike the ground?
At what clock time(s) will the speed of the ball be 5 meters / second?
At what clock time(s) will the ball be 20 meters above the ground?
How high will it be at the end of the sixth second?
answer/question/discussion: ->->->->->->->->->->->-> :
The ball will rise to 34.5m where it will reach a velocity of 0. It will take 2.5 seconds to get to this point. When it hits the ground it will be going about 30m/sec and will reach the ground at about 5.48 seconds. The ball will be going 5m/sec at a clock time of 1 second and the ball would be 20 meters above the ground at a clock time of .53 seconds. I found these answers using a diagram, but I really dont think that I have them right. I am fairly sure that each second the velocity will slow by 10m/sec as the ball moves up, but I am having trouble with the reaching 0 and then beginning to fall phase. How am I supposed to set this up?
** **
25 mins
** **
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#