cq_1_161

Phy 201

Your 'cq_1_16.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** **

A rubber band has no tension until it reaches a length of 7.5 cm. Beyond that length its tension increases by .7 Newtons for every additional centimeter of length.

• What will be its tension if its endpoints are at the points (5 cm, 9 cm) and (10 cm, 17 cm) as measured on an x-y coordinate system?

answer/question/discussion: ->->->->->->->->->->->-> : We need to find the length of the hypotenuse of the triangle made by these points using a^2+b^2=c^2

a=10-5 or 5 cm b=17-9 or 8

so 5^2+8^2=c^2 means that c= 9.43cm

so if the distance is 9.43cm, it is 1.93cm over the length that would have no tension, so we would multiply 1.93cm(.7N) to get 1.35N of tension

• What is the vector from the first point to the second?

answer/question/discussion: ->->->->->->->->->->->-> : We know the distance of the vector, so we need to find the angle/direction. We can do this by taking tan(8/5) which gives an angle of about 60 degrees north of the horizontal.

• What is the magnitude of this vector?

answer/question/discussion: ->->->->->->->->->->->-> : The magnitude is its length which we found using the Pathagorium theorem above. We found its length was 9.43cm.

• What vector do you get when you divide this vector by its magnitude? (Specify the x and y components of the resulting vector).

answer/question/discussion: ->->->->->->->->->->->-> : You get a normalized vector where the magnitude is 1. I am not sure how to figure out the points. A guess would be that since the magnitude of our vector was 9.43, we should put all our units over 9.43 to get a magnitude of one. How would we do this?

• What vector do you get when you multiply this new vector by the tension?

answer/question/discussion: ->->->->->->->->->->->-> : I really do not know what I should do here. We may get the original vector or maybe the vector of tension instead of the total vector?

• What are the x and y coordinates of the new vector?

answer/question/discussion: ->->->->->->->->->->->-> : Again I don’t know how to do this?

** **

25 mins

** **

Very good. Check out the link for the last couple of answers. No need for revision unless you have questions.

&#Please compare your solutions with the expanded discussion at the link

Solution

Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#