cq_1_193

Phy 201

Your 'cq_1_19.3' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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19.3 seed

An object moving in the direction 120 degrees (as measured counterclockwise to the positive x axis) encounters a net force whose direction is 270 degrees.

• Sketch the force and its component along the line of motion, as well as its component perpendicular to the line of motion.

answer/question/discussion: ->->->->->->->->->->->-> : ok

• Suppose you are facing in the direction of motion. Do you perceive the component of the force along the line of motion to be forward or backward? It this component in the direction of motion or opposite to the direction of motion?

answer/question/discussion: ->->->->->->->->->->->-> : I would perceive the motion to be forward if I am facing the motion, it would be moving away from me. This would be the direction of motion? What is this question asking?

• Will the object speed up, slow down or maintain a constant speed?

answer/question/discussion: ->->->->->->->->->->->-> : The object should slow down if it encounters a force.

• If you are facing in the direction of motion, then the line perpendicular to the direction of motion will run to your right and to your left. Is the component of the force perpendicular to the line of motion directed to the right or to the left?

answer/question/discussion: ->->->->->->->->->->->-> : I would assume to the left since the other force is more left.

• Will the object veer to the right, to the left or maintain straight-line motion?

answer/question/discussion: ->->->->->->->->->->->-> : The object should veer right

• Which is greater in magnitude, the component of the force along the line of motion or the component perpendicular to the line of motion?

answer/question/discussion: ->->->->->->->->->->->-> : I would say the component perpendicular to the time of motion. Its angle is larger. I am not really sure how to calculate this if we aren’t given the hypotenuse or another part of the vector.

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15 mins

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For the most part I think you have the right idea and the right orientation. Check out the link to be sure of all the details:

&#Please compare your solutions with the expanded discussion at the link

Solution

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