Phy 201
Your 'cq_1_21.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball is tossed vertically upward and caught at the position from which it was released.
• Ignoring air resistance will the ball at the instant it reaches its original position be traveling faster, slower, or at the same speed as it was when released?
answer/question/discussion: ->->->->->->->->->->->-> : It will be the same speed, it is released with a certain velocity which is counteracted by gravitational pull. It then will fall and regain its velocity. This can also be explained with energy. It is released with a certain amount of KE implying a certain velocity. It then converts this KE to PE which then is reconverted to KE. Conservation of energy says this should be the same so it will be the same velocity.
• What, if anything, is different in your answer if air resistance is present? Give your best explanation.
answer/question/discussion: ->->->->->->->->->->->-> : It depends on which direction air resistance is acting. If it is acting positively with the ball moving upward, more energy will be “added” to the system and the ball will move faster when it is caught. It if is working negatively, then the ball will lose some energy to nonconservative forces and the ball will have a lower KE and lower velocity.
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10 mins
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Good. Read thru the document at the link for a little clarification on how air resistance works in this situation.
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#