Phy 201
Your 'cq_1_24.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec.
• Is the total momentum of the system after collision the same as the total momentum before?
answer/question/discussion: ->->->->->->->->->->->-> : (60g)(80cm/s)+(20g)(0m/s)=60g(50cm/s)+20g(70cm/sec).
No, the initial momentum was greater by 420N.
• What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?
answer/question/discussion: ->->->->->->->->->->->-> :
(60g)(80cm/s)+x(0m/s)=60g(50cm/s)+x(70cm/sec).
Solving for x shows that the marble would have to be 26gs
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10 mins
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&#Your work looks very good. Let me know if you have any questions. &#