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PHY 231
Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
Copy the problem below into a text editor or word processor.
This form accepts only text so a text editor such as Notepad is fine.
You might prefer for your own reasons to use a word processor (for example the formatting features might help you organize your answer and explanations), but note that formatting will be lost when you submit your work through the form.
If you use a word processor avoid using special characters or symbols, which would require more of your time to create and will not be represented correctly by the form.
As you will see within the first few assignments, there is an easily-learned keyboard-based shorthand that doesn't look quite as pretty as word-processor symbols, but which gets the job done much more efficiently.
You should enter your answers using the text editor or word processor. You will then copy-and-paste it into the box below, and submit.
The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
Reasoning would say that by starting at 12 cm/s and increasing at 8cm/sec every second (12 + 8 + 8 + 8) would get you a value of 36cm/sec and the velocity after 3 seconds.
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Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
By adding the starting velocity and the final velocity together (12 + 36) you get a value of 48 and then you can divide that by 2 in order to get the avg. velocity during the interval at 24 cm/sec
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How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
Using the avg. velocity and the time of the interval, you can multiply the 2 values in order to achieve total distance: 24 cm/sec * 3 sec = 72 cm
#$&*
&#Very good responses. Let me know if you have questions. &#
#$&*
PHY 231
Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
Copy the problem below into a text editor or word processor.
This form accepts only text so a text editor such as Notepad is fine.
You might prefer for your own reasons to use a word processor (for example the formatting features might help you organize your answer and explanations), but note that formatting will be lost when you submit your work through the form.
If you use a word processor avoid using special characters or symbols, which would require more of your time to create and will not be represented correctly by the form.
As you will see within the first few assignments, there is an easily-learned keyboard-based shorthand that doesn't look quite as pretty as word-processor symbols, but which gets the job done much more efficiently.
You should enter your answers using the text editor or word processor. You will then copy-and-paste it into the box below, and submit.
The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
Reasoning would say that by starting at 12 cm/s and increasing at 8cm/sec every second (12 + 8 + 8 + 8) would get you a value of 36cm/sec and the velocity after 3 seconds.
#$&*
Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
By adding the starting velocity and the final velocity together (12 + 36) you get a value of 48 and then you can divide that by 2 in order to get the avg. velocity during the interval at 24 cm/sec
#$&*
How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
Using the avg. velocity and the time of the interval, you can multiply the 2 values in order to achieve total distance: 24 cm/sec * 3 sec = 72 cm
#$&*
*#&!
&#Very good responses. Let me know if you have questions. &#