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phy 231
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A ball is tossed vertically upward and caught at the position from which it was released.
Ignoring air resistance will the ball at the instant it reaches its original position be traveling faster, slower, or at the same speed as it was when released?
answer/question/discussion: ->->->->->->->->->->->-> :
Since gravity is considered a conservative force the object would have to be going at the same speed. Also, the net force up is going to be the same as net force down, as well as the work done on the way up and on the way down. With net work equal to 0, the `dKE will also be 0 which means .5*m*vf - .5*m*v0 = 0 that the v doesn’t change.
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What, if anything, is different in your answer if air resistance is present? Give your best explanation.
answer/question/discussion: ->->->->->->->->->->->-> :
The ball would be going slower since air resistance is moving against the ball and therefore causing it to lose energy. There will be less KE at the beginning than at the end because PE should still remain the same, so the loss of energy will show up in the KE.
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Solution
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