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phy 2331
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A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec.
Is the total momentum of the system after collision the same as the total momentum before?
answer/question/discussion: ->->->->->->->->->->->-> :
The momentum is p = mv
InitialM: (0.06 kg * .8m/s) + (.02kg * 0 m/s) = .048 kg m/s
FinalM: (0.06 kg * .5m/s) + (.02kg * .7 m/s) = .044 kg m/s
Differ by slight percentage, the system did not display conservation so there must be something else involved we are not given.
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What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?
answer/question/discussion: ->->->->->->->->->->->-> :
The steel ball’s momentum before collision: .048 kg m/s
The steel ball’s momentum afterwards: .03 kg m/s
.048 kg m/s - .03 kg m/s = .018 kg m/s
The marble must have a velocity to match this momentum
.018 kg m/s / .02kg = .9 m/s
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&#Your work looks very good. Let me know if you have any questions. &#