course Mth 152 ZsMP~٪yassignment #017
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09:53:35 **** query problem 13.4.12 z score for KG's rebounds (.4 from bottom range 10-13)
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RESPONSE --> The problem 13.4.12 is different in the book than the one at the right. 26.3 + 4.3 + 74.2 + 68.9 + 6.8 + 2.7 + .6 + 2.8 + 76.3 + 27.3 = 290.20 290.20 / 10 = 29.20 mean deviations = 2.90 +24.90 + 45.00 + 5.30 + 22.12 + 26.50 + 28.60 + 26.40+ 47.10 + 1.90 deviations squared = 8.41+ 620.01+ 2,025.00 +28.09+ 489.29 + 702.25 + 817.96 + 696.96 +2,218.41 + 3.61 = 7,609.99 7,609.99 / 9 = 29.07 6.8 - 29.20 /29.07 = -22.4 / 29.07= Z =.770
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09:54:21 ** The z score for KG is his total number of rebounds minus the mean average number of rebounds for all the players and then divided by the standard deviation. In KG' s case: z = (489 - 538.2) / 38.8 = -1.3 **
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RESPONSE --> Enter, as appropriate, an answer to the question, a critique of your answer in response to a given answer, your insights regarding the situation at this point, notes to yourself, or just an OK. Always critique your solutions by describing any insights you had or errors you makde, and by explaining how you can make use of the insight or how you now know how to avoid certain errors. Also pose for the instructor any question or questions that you have related to the problem or series of problems. As stated before I worked th problem that was in the book....
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10:06:00 query problem 13.4.30 midquartile same as median? (Q1+Q3)/2
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RESPONSE --> 2,4,6,8,10 median is 6 2,4,6,8,10,12 median = 6 + 8 /2 = 7 I think that the midquartile and the median are the same, as long as the numbers are in numerical order.
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10:06:36 ** If the median is the actual number in the middle, the it's not necessarily equal to the mean of the first and third quartile. There are different ways to see this. For example suppose that in a large set of numbers, the median number is at least 2 greater than the next smaller number and 2 smaller than the next greater number. Then if all the other numbers stay the same, but the median is increased or decreased by 1, it's still in the middle, so it's still the median. Since all the other numbers stay the same, the first and third quartiles are the same as before, so (Q1 + Q3) / 2 is still the same as before. However the median has changed. So if the median was equal to (Q1 + Q3) / 2, it isn't any more. And if it is now, it wasn't before. In either case we see that the median is not necessarliy equal to the midquartile. To be even more specific, the median of the set {1, 3, 5, 7, 9, 11, 13} is 7. The median of the set {1, 3, 5, 8, 9, 11, 13} is 8. The midquartile of both sets is the same, so for at least one of the two sets (namely the second, as you can verify for yourself) the median and the midquartile are different. **
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RESPONSE --> o.k.
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