phy 121
Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds.
• Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s).
answer/question/discussion:
• Sketch a straight line segment between these points.
answer/question/discussion:
• What are the rise, run and slope of this segment?
answer/question/discussion:
Rise = change in y, so rise = 40 cm/s – 10 cm/s = 30 cm/s
Run = change in x, so run = 9 sec – 4 sec = 5 sec
Slope = rise/run, so slope = 30/5, or 6
• What is the area of the graph beneath this segment?
answer/question/discussion:
The area beneath the segment is a trapezoid, so we add the bases (10 + 40 = 50) and divide by 2 (50/2=25). Then, we multiply by the altitude (25 * 5), giving us an area of 125 cm.
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10 min.
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&#This looks very good. Let me know if you have any questions. &#