PHY 121
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
First, we apply the force of gravity by multiplying the each mass by 9.8 m/s^2. This will make the weights of the masses 49 N and 58.8 N. To get net force, we subtract one from the other, leaving us with 9.8 N. The system will accelerate at a rate of 9.8 m/s^2 in the direction of the 6 kg mass.
• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
If the 5kg object is descending at 1.8 m/s when it is released, one second later it will be moving at 8 m/s in the opposite direction (toward the 6kg mass).
• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
During the first second, the velocity and acceleration are in the same direction, and the object will speed up from its original 1.8 m/s to 8 m/s at the end of the one second time period.
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15 minutes
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Solution
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