phy 121
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A steel ball of mass 110 grams moves with a speed of 30 cm / second around a circle of radius 20 cm.
• What are the magnitude and direction of the centripetal acceleration of the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
Acent = v^2/r = (30cm/s)^2 /(20cm)= 900cm^2/s^2 / 20 cm = 45 cm/s^2
• What is the magnitude and direction of the centripetal force required to keep it moving around this circle?
answer/question/discussion: ->->->->->->->->->->->-> :
First, convert cm to meters to get .45 m/s^2, and grams to kg to get .11 kg
Fcent = a cent * m = .45 m/s^2 * .11 kg = 0.495 N
The required force must be perpendicular to the radius of the circle as measured from the center to the ball.
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15 minutes
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Good, but see the link below regarding the direction and let me know if you have questions:
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Solution
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