Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
What is the clock time at the midpoint of this interval?
The midpoint of the graph is at 9sec. I got this from the difference of the two (t) times, being the duration of time (8sec) and half of that is 4 sec.
What is the velocity at the midpoint of this interval?
The velocity at the midpoint would be 28cm/s. 24cm's is the total change in velocity and half of that is 12cm/s. Which results in 28cm/s when you add the 16cm/s at the midpoint to half the change in velocity (12cm/s).
Good. Alternatively you could just average the initial and final velocities to get the same result.
How far do you think the object travels during this interval?
I believe the object to travel 192cm. I got this by the product of time and change in velocity. 8sx24cm/s=192cm
By how much does the clock time change during this interval?
The clock changes by 8 seconds.
By how much does velocity change during this interval?
The velocity changes by 24cm/s. I took this from the points on the graph, (40cm/s - 16cm/s).
What is the rise of the graph between these points?
The rise between the two points on the graph is 8 seconds.
On a graph of velocity vs. clock time this would be the run.
What is the run of the graph between these points?
The run between the two points on the graph is 24cm/s.
What is the slope of the graph between these points?
Rise OVER Run= 1s/(3cm/s)
Inverting your result to reverse your rise and run would give you 3 cm/s/s, or 3 cm/s^2.
On a graph of velocity vs. clock time this would be the rise.
What does the slope of the graph tell you about the motion of the object during this interval?
It depicts that the object is increasing in speed.
What is the average rate of change of the object's velocity with respect to clock time during this interval?
The object is increasing in velocity 3cm per second.
That would be 3 cm/s/s or 3 cm/s^2, and coincides with the slope of the v vs. t graph.
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20 min
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&#Your work looks good. See my notes. Let me know if you have any questions. &#